因为短日期不足2位,所以在网页排版的时候,影响美观,下面两个函数可以解决这个问题。
2020-2-7短日期 变 2020-02-07长日期
Function FStime(times) Dim years,months,days if len(times)=0 then exit function years=year(times) months=right("0"&month(times),2) days=right("0"&day(times),2) times=years&"-"&months&"-"&days FStime=times End Function
2020-2-7 23:37:5短日期 变 2020-02-07 23:37:05长日期
Function FLtime(times) Dim years,months,days,hours,minutes,seconds if len(times)=0 then exit function years=year(times):months=right("0"&month(times),2) days=right("0"&day(times),2):hours=right("0"&hour(times),2) minutes=right("0"&minute(times),2):seconds=right("0"&second(times),2) FLtime=years&"-"&months&"-"&days&" "&hours&":"&minutes&":"&seconds End Function
Pw_Sys 日期格式转换函数
<% Rem Pw_Sys 日期格式转换函数 function DateTimeFormat(DateTime,Format) select case Format case "1" DateTimeFormat=""&year(DateTime)&"年"&month(DateTime)&"月"&Right("0" & Day(DateTime),2)&"日" case "2" DateTimeFormat=""&month(DateTime)&"月"&Right("0" & Day(DateTime),2)&"日" case "3" DateTimeFormat=""&year(DateTime)&"-"&month(DateTime)&"-"&Right("0" & Day(DateTime),2)&"" case "4" DateTimeFormat=""&year(DateTime)&"/"&month(DateTime)&"/"&Right("0" & Day(DateTime),2)&"" case "5" DateTimeFormat=""&month(DateTime)&"/"&Right("0" & Day(DateTime),2)&"" case "6" DateTimeFormat=""&year(DateTime)&"年"&month(DateTime)&"月"&Right("0" & Day(DateTime),2)&"日<font color=red> "&FormatDateTime(DateTime,4)&"</font>" case "7" temp="星期日,星期一,星期二,星期三,星期四,星期五,星期六" temp=split(temp,",") DateTimeFormat=temp(WeekRight("0" & Day(DateTime),2)-1) case "8" DateTimeFormat=""&month(DateTime)&"-"&Right("0" & Day(DateTime),2)&"" case "9" if len(hour(DateTime)) = 1 then str="0"&hour(DateTime) else str=hour(DateTime) end if DateTimeFormat=DateTimeFormat(DateTime,1)&" "&str&":"&Minute(DateTime) case "10" DateTimeFormat=""&year(DateTime)&"年"&month(DateTime)&"月" case else DateTimeFormat=DateTime end select end function %>
程序代码(把yyyy-mm-dd格式的日期中的月份和日期转换成两位数字的方法)
dim today
today=Date "避免重复调用Date,所以赋值给一个变量
today=Year(today) & "-" & Right("0" & Month(today),2) & "-" & Right("0" & Day(today),2)
asp中一段自动补位的函数
function formatsn(getnum,getbit) dim formatsnnum,formatsnpre,formatsnj formatsnnum = getbit – len(getnum) for formatsnj = 1 to formatsnnum formatsnpre = formatsnpre & "0" next formatsn = formatsnpre & getnum end function
使用方法
formatsn(getnum,getbit)
getnum 计数
getbit 共几位
以上就是ASP中格式化时间短日期补0变两位长日期的方法的详细内容,更多关于ASP短日期补0的资料请关注其它相关文章!
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