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Oracle递归查询树形数据实例代码

【字号: 日期:2023-03-08 16:57:33浏览:6作者:猪猪
目录
  • 概述
  • 1、数据准备
  • 2 start with connect by prior递归查询
    • 2.1 查询所有子节点
    • 2.2 查询所有父节点
    • 2.3 查询指定节点的根节点
    • 2.4 查询下行政组织递归路径
  • 3 with递归查询
    • 3.1 with递归子类
    • 3.2 递归父类
  • 4 MySQL 递归查找树形结构
    • 总结

      概述

      实际生活有很多树形结构的数据,比如公司分为多个部门,部门下分为多个组,组下分为多个员工;省市县的归属;页面菜单栏等等。

      如果想查询某个节点的父节点或者子节点,一般通过表自身连接完成,但如果该节点的子节点还有多层结构,就需要使用递归调用。但如果数据量特别大,递归的次数指数级上升,而且查询数据库的次数也指数级上升,导致程序和数据库压力剧增,查询时间特别长。那数据库有没有递归查询语句呢?答案是肯定的。

      start with connect by prior 递归查询

      1、数据准备

      create table area_test(
        id         number(10) not null,
        parent_id  number(10),
        name       varchar2(255) not null
      );
      
      alter table area_test add (constraint district_pk primary key (id));
      
      insert into area_test (ID, PARENT_ID, NAME) values (1, null, "中国");
      insert into area_test (ID, PARENT_ID, NAME) values (11, 1, "河南省"); 
      insert into area_test (ID, PARENT_ID, NAME) values (12, 1, "北京市");
      insert into area_test (ID, PARENT_ID, NAME) values (111, 11, "郑州市");
      insert into area_test (ID, PARENT_ID, NAME) values (112, 11, "平顶山市");
      insert into area_test (ID, PARENT_ID, NAME) values (113, 11, "洛阳市");
      insert into area_test (ID, PARENT_ID, NAME) values (114, 11, "新乡市");
      insert into area_test (ID, PARENT_ID, NAME) values (115, 11, "南阳市");
      insert into area_test (ID, PARENT_ID, NAME) values (121, 12, "朝阳区");
      insert into area_test (ID, PARENT_ID, NAME) values (122, 12, "昌平区");
      insert into area_test (ID, PARENT_ID, NAME) values (1111, 111, "二七区");
      insert into area_test (ID, PARENT_ID, NAME) values (1112, 111, "中原区");
      insert into area_test (ID, PARENT_ID, NAME) values (1113, 111, "新郑市");
      insert into area_test (ID, PARENT_ID, NAME) values (1114, 111, "经开区");
      insert into area_test (ID, PARENT_ID, NAME) values (1115, 111, "金水区");
      insert into area_test (ID, PARENT_ID, NAME) values (1121, 112, "湛河区");
      insert into area_test (ID, PARENT_ID, NAME) values (1122, 112, "舞钢市");
      insert into area_test (ID, PARENT_ID, NAME) values (1123, 112, "宝丰市");
      insert into area_test (ID, PARENT_ID, NAME) values (11221, 1122, "尚店镇");
      

      2 start with connect by prior递归查询

      • start with 子句:遍历起始条件。如果要查父结点,这里可以用子结点的列,反之亦然。
      • connect by 子句:连接条件。prior 跟父节点列parentid放在一起,就是往父结点方向遍历;prior 跟子结点列subid放在一起,则往叶子结点方向遍历。parent_id、id两列谁放在 “=” 前都无所谓,关键是prior跟谁在一起。
      • order by 子句:排序。

      常用的select项:

      LEVEL:级别
      connect_by_root:根节点
      sys_connect_by_path:递归路径

      2.1 查询所有子节点

      select t.*,LEVEL
      from area_test t
      start with name ="郑州市"
      connect by prior id=parent_id
      

      其实,如果单层结构,使用表自身连接也可以实现:

      select * from area_test t1,area_test t2 
      where t1.PARENT_ID = t2.ID and t2.name="郑州市";
      

      当查询节点下有多层数据:

      select t.*,LEVEL
      from area_test t
      start with name ="河南省"
      connect by prior id=parent_id
      

      select * from area_test t1,area_test t2 
      where t1.PARENT_ID = t2.ID and t2.name="河南省";
      

      如果使用自身连接,也只能查到子一级节点的数据,需要遍历子一级节点,递归查询每个子一级节点下的子节点。明显麻烦很多!!!

      2.2 查询所有父节点

      select t.*,level
      from area_test t
      start with name ="郑州市"
      connect by prior t.parent_id=t.id
      order by level asc;
      

      2.3 查询指定节点的根节点

      select d.*,
      	   connect_by_root(d.id) rootid,
      	   connect_by_root(d.name) rootname
      from area_test d
      where name="二七区"
      start with d.parent_id IS NULL
      connect by prior d.id=d.parent_id
      

      select d.*,
      	   connect_by_root(d.id) rootid,
      	   connect_by_root(d.name) rootname
      from area_test d
      start with d.parent_id IS NULL
      connect by prior d.id=d.parent_id
      

      2.4 查询下行政组织递归路径

      select id, parent_id, name, sys_connect_by_path(name, "->") namepath, level
      from area_test
      start with name = "平顶山市"
      connect by prior id = parent_id
      

      3 with递归查询

      3.1 with递归子类

      with tmp(id, parent_id, name) 
      as (
      	select id, parent_id, name
          from area_test
          where name = "平顶山市"
          union all
          select d.id, d.parent_id, d.name
          from tmp, area_test d
          where tmp.id = d.parent_id
         )
      select * from tmp;
      

      3.2 递归父类

      with tmp(id, parent_id, name) 
      as
        (
         select id, parent_id, name
         from area_test
         where name = "二七区"
         union all
         select d.id, d.parent_id, d.name
         from tmp, area_test d
         where tmp.parent_id = d.id
         )
      select * from tmp;
      

      4 MySQL 递归查找树形结构

      参考文章:MySQL 递归查找树形结构,这个方法太实用了

      参考文章:Oracle递归查询

      总结

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      标签: Oracle